Homework SourseWhat is the period of a simple pendulum 88 m cm long on the
What is the period of a simple pendulum 88 {\ m cm} long on the Earth?
What is the period of a simple pendulum 80 {\ m cm} long when it is in a freely falling elevator?
What is the period of a simple pendulum 80 {\ m cm} long when it is in a freely falling elevator?
Solution
length of the pendulum L = 88 cm
acceleration due to gravity is g = 9.8 m/s2
time period T = 2L/g
= (2)(3.14){(88*10-2 m) / (9.8 m/s2)}
= 1.88 s
..........................................................................
for free falling elevator, the relative acceleration observwd as a = g = 0 m/s2
hence,
time period T = 2L/g
= (2)(3.14){(88*10-2 m) / (0 m/s2)}
= infinite
hence,
time period T = 2L/g
= (2)(3.14){(88*10-2 m) / (0 m/s2)}
= infinite
= (2)(3.14){(88*10-2 m) / (0 m/s2)}
= infinite
