Linear Algebra Please show all work steps and calculations T
Linear Algebra
Please show all work steps and calculations. Thank you.
Solution
3. T: R3?R2 is defined by T(x,y,z) = (x+y,y+z).
(a). We have T(e1) = T(1,0,0) = (1,0) , T(e2) = T(0,1,0) = (1,1) and T(e3) = T(0,0,1) = (0,1). Hence [T] = A= [ T(e1) , T(e1) , T(e1) ] =
1
1
0
0
1
1
(b).Ker(T) is the set of solutions to the equation AX = 0. To solve this equation, we have to reduce A to its RREF as under:
Add -1 times the 2nd row to the 1st row
Then the RREf of A is
1
0
-1
0
1
1
Now, if X = (x,y,z)T, then the equation AX = 0 is equivalent to x-z = 0 or, x = z and y+z = 0 or, y = -z. Then X = (z,-z,z)T= z(1,-1,1)T.Hence, {(1,-1,1)T } is a basis for ker(T).
| 1 | 1 | 0 |
| 0 | 1 | 1 |