Problem 5 What is the angular momentum vector of the 500 g r

Problem #5 What is the angular momentum vector of the 500 g rotating bar in this figure? 120 rpm 2.0 m

Solution

Given that,

m = 500 g = 0.5 kg

l = 2 m

w = 120 rpm = 12.57 rad/s

Moment of inertia of bar about given axis,

l = (1/12)*ml^2

l = (1 / 12)*0.5*2^2 = 0.166 kg.m^2

Angular momentum,

L = l*w

L = 0.166*12.57

L = 2.094 kg.m^2 / s