If you combine 4000 mL of water at 2500 degree C and 1200 mL

If you combine 400.0 mL of water at 25.00 degree C and 120.0 mL of water at 95.00 degree C. what is the final temperature of the mixture? Use 1.00 g/m L as the density of water.

m1= 400 g
T1 = 25 oC
m2 = 120 g
T2 = 95 oC
let the final temperature be ToC

use:
heat lost my m2 = heat gained by m1
m2*c*(T2-T) = m1*c*(T-T1)
m2*(T2-T) = m1*(T-T1)
120*(95-T) = 400*(T-25)
11400 - 120*T = 400*T - 10000
T = 41.15 oC