85 A roller coaster going 192 ms starts up a hill Ignoring

85. . A roller coaster going 19.2 m/s starts up a hill. Ignoring friction, what?s its speed after it has risen 1 2.2 m vertically?

Solution

here

From conservation of Energy

KEi = KEf + Potential Energy at that Height

0.5mvi^2 = 0.5*m*vf^2 + m*g*h

vi^2 = vf^2 + g*h

Vf = sqrt(vi^2-gh)
vf = sqrt(19.2^2 - 9.8*12.2)
vf = sqrt(368.64 - 119.56)
Vf = 15.78 m/s