A 200 F capacitor is charged to 170 C and then connected acr

A 20.0 F capacitor is charged to 170 C and then connected across the ends of a 5.80 mH inductor.

A) Find the maximum current in the inductor.

B) At the instant the current in the inductor is maximal, how much charge is on the capacitor plates?

C) Find the maximum potential across the capacitor.

D) At the instant the potential across the capacitor is maximum, what is the current in the inductor?

E) Find the maximum energy stored in the inductor.

F) At the instant the energy stored in the inductor is maximum, what is the current in the circuit?

Please show work and explain clearly! Thank you!!

a) the energy stored in capacitor = 0.5 *( q²/ C) = 7.225x10^-4 J

this energy will be stored in inductor in the form of 0.5 LI ² = 7.225x10^-4 J

so , I ²= 0.249

=> I = 0.499 A

b) as all the charge is transferred to inductor charge will be 0

c) maximum potential will be when it holds maximum charge = 170micro C

so, potential V= Q/C = 170/ 20 =8.5 V

d) the current will be zero , as the total energy is stored in capacitor and no energy is stored in inductor .

e) maximum enrgy stored in inductor = 0.5 LI²

where I is the maximum current = 0.499 A

so energy = 0.5 * 5.80x10^-3 * 0.499 ²=7.22 x10^-4 J

f) there will be no current in the capacitor as the total energy is stored in the inductor