Balance out these equations FeSO4 K4FeCN6 Fe4FeCN63 FeSO

Balance out these equations:

FeSO4 + K4Fe(CN)6 = Fe4[Fe(CN)6]3 + ??

FeSO4 + K3Fe(CN)6 = ??

FeCl3 + K4Fe(CN)6 = ??

FeCl3 + K3Fe(CN)6 = ??

In some of these, I should also get K2Fe2(CN)6, but I do not know in which one.

In acid: Fe2O3 + CO => Fe + CO2

In acid: HCOOH + MnO4 - => CO2 + Mn2+

In acid: P + Cu2+ => Cu + H2PO4 -

In base: CO + I2O5 => CO2 + I2

In base: Cr(OH)3 + Br2 => CrO4 2- + Br-

Solution

1).

3 K₄(Fe(CN)₆) + 6 FeSO₄ = Fe₄[Fe(CN)₆]₃ + 6 K₂SO₄ + Fe₂

Fe4[Fe(CN)6]3 is the Prussian blue or Berlin blue.

2).

4K₃[Fe(CN)₆] + 3FeSO₄ Fe₄[Fe(CN)₆]₃ + 3K₂SO₄ + 6KCN

Potassium hexacyanoferrate(III) react with iron(II) sulfate to produce iron(III) hexacyanoferrate(II), potassium sulfate and potassium cyanide.

3).

FeCl3 + K4[Fe(CN)6] ==> KFe[Fe(CN)6] + 3 KCl

Iron(III) chloride react with potassium hexacyanoferrate(II) to produce potassium diiron(III) hexacyanoferrate and potassium chloride.

4).

K₃[Fe(CN)₆] + FeCl₃ Fe[Fe(CN)₆] + 3KCl

Potassium hexacyanoferrate(III) react with iron(III) chloride to produce iron(III) hexacyanoferrate(III) and potassium chloride.