Physics How much total heat transfer is 275 including the t

Physics How much total heat transfer is -27.5 , including the to lower the temperature of 0.295 kg of steam from 1295°C to ges? much time is required for each stage of this process, assuming a constant 855.0 W rate of heat change? Give the times in the order that the stages occur Number Number

Solution

m =0.295 kg , T1 =129.5 oC, T2 =-27.5 oC

P =855 W

specific heat of water 4186 J/kg.K

specifice heat of steam = 2051 J/kg.K

specific heat of ice L = 2051 J/kg.K

Latent heat of steam = 2230*10^3 J/kg

Latent heat of ice = 334*10^3 J/k

Q = (0.295*2051*(129.5-100)) +(0.295*2230*10^3)+(0.295*4186*(100-0))+(0.295*334*10^3)+(0.295*2051*(0+27.5))

Q = 9.14*10^5 J

P = Q/t

855 = (0.295*2051*(129.5-100))/t1

t1 = 20.88 s

855 = (0.295*2230*10^3)/t2

t2 = 769.4 s

855 = (0.295*4186*(100-0))/t3

t3 = 144.43 s

855 = (0.295*334*10^3)/t4

t4 = 115.2 s

855 = (0.295*2051*(0+27.5))/t5

t5 =19.46 s