In an empty rubber raft the pressure is approximately consta

In an empty rubber raft the pressure is approximately constant. You push on a large air pump that pushes 1.0 L(1.0× 103m3) of air into the raft. You exert a 20 N force while pushing the pump handle 5.0×102 m .

Part A Determine the work done on the gas.

Part B If all of the work is converted to thermal energy of the 1.0 L of gas, what is the temperature increase of the gas? Assume that the air obeys the ideal gas law and is initially at 293 K.

Solution

A) Work done = W = 20*(5.0*10^-2) = 1.0 J

B) As PV = nRT =====> nR = PV/T = P*10^-3/293 = 3.41*10^-6*P

U=nCvT = (3/2)*n*R*T

T = U/[(3/2)*n*R] = 1/[1.5*P*3.41*10^-6] = 195503.42/P

Put value of P and find T


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