This next diagram shows an electric field Were not going to
Solution
B-1) The given field lines are drawn for a positive charge as they point outwards from the charge.
Point J has higher electric potential than point K. Because the potential at a point decreases with the increase in distance from the point charge (V = k Q / r ). We see from the figure that the distance of J is lesser than K from the charge and hence K has higher potential.
B-2)The electric field will be stronger at J only beacuse again the distance of point J from the charge than point K is lesser and we know that electric field at any point is inversely proportional to the square of distance from the point charge (E = k Q/r2 ).
Hence, the field is stronger at J than K.
C-1) the given field lines seems to be that of line charge.
the electric potential at D and E will be equal and lesser at F. Because the distance of D and E is same from the line of charge where as F is larger than that of D and E.
2)the electric field will be the same way, equal at D and E and lesser at F.Because the distance of D and E is same from the line of charge where as F is larger than that of D and E.
D)