A hollow spherical shell with mass 210 kg rolls without slip

A hollow spherical shell with mass 2.10 kg rolls without slipping down a slope that makes an angle of 30.0 with the horizontal.

Find the magnitude of the acceleration a_cm of the center of mass of the spherical shell. Take the free-fall acceleration to be g = 9.80 m/s²

Find the magnitude of the frictional force acting on the spherical shell.

Solution

A) accelaration a = (3/5)*g*sin(theta) = (3/5)*9.81*sin(30) = 2.943 m/s^2

B) Frictional force (2/5)*m*g*sin(30) = (2/5)*2.1*9.81*0.5 = 4.12N