A diverging lens has a focal length that has a magnitude of
A diverging lens has a focal length that has a magnitude of 31.0 cm. An object is placed 18.0 cm in front of this lens. Calculate the magnification.
Ans:_____________
Solution
for diverging lens,
f = -31 cm
do = 18 cm
Applying Lens equation,
1/f = 1/do + 1/di
1/(-31) = 1/18 + 1/di
di = - 11.4 cm
magnification = - (di / do) = - ( - 11.4 / 18) = 0.63
