A uniform sign is supported against a wall at point P If the

A uniform sign is supported against a wall at point P. If the sign is a square 0.90 m on a side and its mass is 5 kg, what is the magnitude of the horizontal force that the wall at P experiences?

A. 0.00 N

B. 17 N

C. 25 N

D. 49 N

Please show all work and a picture if possible!!!!

Solution

Correct option is (C)

m =5 kg , g =9.8 m/s^2

Net torque about an axis passin through P is zero

Torque= rxF

Torque due to horizontal force =Torque due to weight

here r is perpendicular distance.

dF = (d/2)w

F = w/2 = mg/2 = 5*9.8/2

F =25 N