Sm Digital Resources for Chemistry 112617 CH07 Required HW T
Solution
C% = 12*wt of Co2*100/44* wt of compound
= 12*84.4*100/44*31.1 = 74%
H% = 2*wt of H2O *100/18*wt of compound
= 2*17.3*100/18*31.1 = 6.18%
O% = 100-(C%+ H%)
= 100-(74+6.18) = 19.82%
Element % A.wt relative number simple ratio
C 74 12 74/12 = 6.16 6.16/1.24 = 5
H 6.18 1 6.18/1 = 6.18 6.18/1.24 = 5
O 19.82 16 19.82/16 = 1.24 1.24/1.24 = 1
The empirical formula of the compound = C5H5O
The empirical formula weight = 12*5 +1*5 + 16 = 81g/mole
molecular weight = 162g/mole
molecular formula = (empirical formula)n
n = M.Wt/E.F.Wt
= 162/81 = 2
The molecular formula = (C5H5O)2 = C10H10O2