Homework SourseA coin is placed 90 cm in front of aconcave mirror The mirro
A coin is placed 9.0 cm in front of aconcave mirror. The mirror produces a real image that has adiameter 5.0 times larger than that ofthe coin. What is the image distance?
Solution
as from the given
object distance
do = 9.0 cm
the height of the image is
h\' = 5 h
the magnification is given by
M = h\' / h
= - di /do
solve for the image distancedi
