A Consider the balanced equation 2A 5B 3C D 8 mol A are mi

A) Consider the balanced equation:

2A + 5B 3C + D

8 mol A are mixed with 15 mol B at an elevated temperature. After 6mol of A have reacted, how much B is left?

B) Consider the balancedequation:

2A + 5B 3C + D

0.40 mol A are mixed with 1.16 mol B at an elevated temperature.After 0.28 mol of A are left, how much B isleft?

B) Consider the balancedequation:

2A + 5B 3C + D

0.40 mol A are mixed with 1.16 mol B at an elevated temperature.After 0.28 mol of A are left, how much B isleft?

Solution

Yes, 15 moles reacted, leaving you with 0 mols after the reactionbased off of how many mols of A there were. Try 15 mol backwardsand you will get how many moles of A has reacted. It should be6. Like for the next one. You have .28 mol of A left so take the moleratio of times 5 divided by 2 and you get the number of molesreacted for B. So then take 1.16 mol B - how many reacted = Leftover mol of B Sorry if I was not too clear. Hope that was better.

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