previous 8 of 13 roblem 2927 Part A An electron moves in the

previous 8 of 13 roblem 29.27 Part A An electron moves in the magnetic field B- 0.600 iT with a speed of 0 800 x107 m/s in the directions shown in the figure. For each, what is magnetic force F on the electron? aurel) Express vector F in the form of F. Fy. F, where the x, y, and z components are separated by commas. Submit My Answers Give Up Paree Express vector F in the form of F. F, F., where the x y, and z components are separated by commas. Figure 1 of Submit My Answers Giee U Provide Feedback C

Solution

a) The force on a charged particle moving in an external magnetic field will follow:

                                      F = q(v x B)

The angle between the velocity vector and magnetic field vector is 90 degrees

                                       F = qvB*sin = -1.6*10^-19*0.8*10^7*0.6*sin90 = -7.68*10^-13 N

The velocity and magnetic field vectors form a plane on the x-y plain. Using the right hand rule,

the force is pointing in the positive z-direction.

                                    F = (-7.68*10^-13 k^) N

b) The velocity vector can be written like:

               v = vx i^ + vy j^ + vz k^

                vx = 0 m/s

                vy = -v*cos45

                vz = v*sin45

Now solve for the force vector           F = q*v x B

F = qv(-cos45 j^ + sin45 k^) x (0.60 i^)

   = -1.6*10^-19*0.8*10^7*[cos45*0.6 k^ + sin45*0.6 j^]

   = (-5.43*10^-13 N) (j^ + k^)