90 F 46 02 560 F Figure 3 Picture of the setup in problem 6

-90 F 4.6 =02 5,-60 F Figure 3: Picture of the setup in problem 6 6.) EXTRA CREDIT: For the circuit pictured in Figure 3, (a) Set-up the system of three equations that would allows us to find the currents 1, 12, and 13 (b) Use your solution from part (a.) to find the currents 1, 12, and la

Solution

here,

let the current through the batteries be i1 , i2 and r4 throught i3

using KVL in the upper loop

( 0.04 + 6 + 6 ) * i1 - 0.2 * i2 = E1 - E2

( 0.04 + 6 + 6 ) * i1 - 0.2 * i2 = 90 - 60 ....(1)

and

using KVL in the lower loop

(1.5 + 2.4) * i3 + 0.2 * i2 = E2

(1.5 + 2.4) * i3 + 0.2 * i2 = 60 .....(2)

and

using KCL

i3 = i1 + i2 ....(3)

from (1) and (2)

i1 = 2.69 A

i2 = 12.1 A

i3 = 14.8 A