3 1 points SerCP11 7P051 My Notes Ask Your Teacher An athlet

3. 1 points SerCP11 7.P.051 My Notes Ask Your Teacher An athlete swings a 4.00-kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.890 m at an angular speed of 0.610 rev/s. (a) What is the tangential speed of the ball? m/s (b) What is its centripetal acceleration m/s2 (c) If the maximum tension the rope can withstand before breaking is 82 N, what is the maximum tangential speed the ball can have? m/s Need Help? Read It Show My Work (Optional) @

Solution

Here ,

a) angular speed , w = 0.610 rev/s

w = 0.610 * 2pi = 3.83 rad/s

r = 0.890 m

a) tangential speed = r * w

tangential speed = 0.890 * 3.83

tangential speed = 3.41 m/s

b)

centripetal acceleration = w^2 * r

centripetal acceleration = 3.83^2 * 0.890

centripetal acceleration = 13.1 m/s^2

c)

as F = m * v^2/r

82 = 4 * v^2/0.890

v = 4.27 m/s

the maximum tangential speed of the ball is 4.27 m/s