8 ry using the 8bit signed2scomplement representation Then p
Solution
8. +75
So we will write binary for 75 i.e 01001011 and thats it because in 2\'complememt for positive numbers we just need their binary.
Similarly for +53 we will have 0011 0101
-106 + (-72)
-106 - first we will write binary of 106 , we will do 1\'s complement and then add 1
so 106 = 0110 1010
1001 0101 (1\'s complement)
1001 0101
+ 1
---------------
10010110
Similarly for -72 we have:
0100 1000
1011 0111 (1\'s complement)
+ 1
-------------
1011 1000
Solving -106 + (-72) = 01001110 (in binary) (1 bit is overflowing). If we convert this to decimal we get 78 and not -178
If we solve -106 -72 we get -178
If we look at the 2\'s complement of -178 it is
1011 0010 (Binary)
0100 1101 (1\'s complement)
+ 1
------------
01001110 --> This matches with our answer.
Convert 11 0011 1000 1111 0000 1010 1110 1011 to hexadecimal
338F0AEB