3 An object is thrown with a horizontal velocity of 20 air r
Solution
h = ut + 0.5gt^2
Here Initial vertical velocity , u = 0, since the object is thrown horizontally
125 = 0*t + 0.5*9.81*t^2
125 = 4.905*t^2
t = 5.05 s
So option is (b) 5 s
h = ut + 0.5gt^2
Here Initial vertical velocity , u = 0, since the object is thrown horizontally
125 = 0*t + 0.5*9.81*t^2
125 = 4.905*t^2
t = 5.05 s
So option is (b) 5 s