A steel wire in a piano has mass of 43 grams If tension in w
A steel wire in a piano has mass of 4.3 grams. If tension in wire is 5.12 what must be length of the string in m in order that fundamental vibration in Hz corresponds to middle C f261.6 Hz
A steel wire in a piano has mass of 4.3 grams. If tension in wire is 5.12 what must be length of the string in m in order that fundamental vibration in Hz corresponds to middle C f261.6 Hz
Solution
Relevant equations to solve the problem are:
1) v = Sqr(Tension(T)/mass per unit length(m/l))
2) v=(wave length(lambda)*frequency(f)
length is not given
mass per unit length = (0.0043kg/l m)
Since we are looking for the fundamental vibration, or first harmonic, and the string is attached at both ends, our wve lenght is (2* lm) or 2l m
Using the second equation, we can solve for v:
v=(2l) *f=523.2 l m/s
Then, we can solve for the tension by pluging our known pieces into the first equation.
523.2 l = Sqr(5.12/m/l)
273738.24 l*m = 5.12
1177 l=5.12
l=4.349 *10-3 m