Two point charges 15 nC each are located at points 25 m0 and

Two point charges, 1.5 nC each, are located at points (25 m,0) and (-25 m,0). What is the potential at point (0, 2 m)?

Solution

distance of point of interest from first two charges = squareroot(25² + 2²) = 25.08 m

Potential energy = kq₁/r + kq₂/r

= 2kq₁/r

= 2*9*10⁹*1.5*10^-9 / 25.08 = 1.076 V