A 25 cm times 25 cm times 25 cm box with its edges aligned w

A 2.5 cm times 2.5 cm times 2.5 cm box with its edges aligned with the xyz-axes is in the electric field E = (380x + 130)I cap N/C, where x is in meters. What is the net electric flux through the box? Phi = _________

Solution

According to the question

We know that

volume of box , V = 2.5 cm * 2.5 cm * 2.5cm

area of one face , A = 0.025^2 m^2

Then,

A = 0.0625m^2

the net electric flux , Flux = E * A

flux = (380*0.25+130) * A - (380 * 0 + 130)* A

Then,

flux = 380 * 0.25 * 0.0625

So,

flux = 5.89 * 10^-3 Nm^2/C

the net electric flux is 5.89 * 10^-3 Nm^2/C